Yes, I am intrigued by such question: how much really a tree or forest can capture or sequester the CO2 released anthropogenically (fossil fuel and natural gas being the primary target)?
Thus, I set out to search for the calculations, and awared that a lot of people are using tree/plant for CO2 sequesteration program, like in the carbon offset bussiness. This whole bussiness thing is a complex one, and my question is relatively a simple or crude one: how much CO2 is absorbed or sequestered by tree/plant or forest in a quantitative way?
Few values or data related to this field are found. Let’s start with the number from established organization like Environmental Protection Agency, US:
Claim#1: Afforestation: 0.6 to 2.6 metric tons of C per acre per year.
Reforestation: 0.3 – 2.1 metric tons of C per acre per year.
Next, in this report, it is claimed that:
Claim#2 (a): … 1 m3 of growth in forest biomass (stem, roots, branches, etc.) absorbs 0.26 tCe (Brown et al., 1986), … the average rate of growth is 15 m3/ha/year. And,
Claim#2 (b): This is equivalent to 815 million (m^3) bone-dry tonnes of wood, which in turn corresponds to 0.41 GtCe.
Claim#2 (c): Assuming a yield for hardwoods of 35 m3/ha/year, this would mean sequestering about 9 tCe of CO2 /ha/year.
According this paper:
Claim#3: In addition, the rate of C sequestration based on biomass change in vegetation was recorded to assess the optimum land use that can absorb the carbon dioxide emitted by the power project. These are as follows: (a) tree plantations (10.09 tC/ha/yr) >coconut (4.78 tC/ha/yr) >brushland (4.29 tC/ha/yr) > (b) natural forest (0.92 tC/ha/yr).
Ok, now it is time to make all these data comparable, if possible:

Thus, let’s say if I need to plant the tree to capture or sequester the CO2 which spewed by my car, as calculated here, with a daily mileage of 25km and emitted roughly 1104.1 kg CO2, or 301.1 kg of Carbon equivalent (1 tonne Carbon equivalent = 3.667 tonnes CO2) per year, I would need:
Claim#1 (a): Afforestation area = 0.301 ÷ 3.633 = 0.0828 ha = 828 m^2.
Claim#1 (b): Afforestation area = 0.301 ÷ 15.873 = 0.0190 ha = 190 m^2.
Claim#2 (c): Hardwood plant area = 0.301 ÷ 9.00 = 0.0334 ha = 334 m^2 .
Claim#3 (a): Tree plantation area = 0.301 ÷ 10.09 = 0.030 ha = 300 m^2.
Claim#3 (b): Natural forest area = 0.301 ÷ 0.920 = 0.327 ha = 3270 m^2.
Claim#2 (a): Biomass volume required = 0.301 ÷ 0.260 = 1.157 m^3.
Claim#2 (b): Biomass volume of bone-dry woods required = 0.301 ÷ 0.503 = 0.598 m^3.
So, an area ranging from 190 m^2 to 3270 m^2, depending on the efficiency of carbon sequesteration rate (which in turn a lot of factors are playing in) is required to absorb/capture the amount of CO2 emitted via my car. I wonder how much do I have to spend if I bought the land in Malaysia in order to do this? And if 26 millions of Malaysians need to do this, how much land area is required, per year? Hmmmm….










Gerald Van Bommel said,
August 13, 2007 at 5:15 pm
You need to factor in the fact that when the tree decays it will release carbon in the form of methane which is a far worse greenhouse gas than carbon dioxide.
mich said,
August 13, 2007 at 11:58 pm
Well, the tree will grow and live for at least few tens years, and hardwood type tree do not decay easily, so I do not factor in the release of C yet…